3X^2+2x-380=0

Solution for 3X^2+2x-380=0 equation:

3X^2+2X-380=0

a = 3; b = 2; c = -380;
Δ = b2-4ac
Δ = 22-4·3·(-380)
Δ = 4564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4564}=\sqrt{4*1141}=\sqrt{4}*\sqrt{1141}=2\sqrt{1141}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1141}}{2*3}=\frac{-2-2\sqrt{1141}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1141}}{2*3}=\frac{-2+2\sqrt{1141}}{6}
$